\begin{axiom}\label{phase7_concurrent_earlier_axiom}
    For all $x$ we have $x = x$.
\end{axiom}

\begin{proposition}\label{phase7_concurrent_earlier_failure}
    For all $x$ we have $x = x$.
\end{proposition}
\begin{proof}
    Fix $x$.
    Follows by assumption.
\end{proof}