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diff --git a/library/set/cantor.tex b/library/set/cantor.tex
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@@ -16,7 +16,5 @@
Take $a'$ such that $a'\in A$ and $f(a') = B$ by \cref{surj}.
We have if $a'\in B$, then $a'\notin B$ by assumption.
We have if $a'\notin B$, then $a'\in B$ by assumption.
- We have $a'\in B$ by assumption.
- We have $a'\notin B$ by assumption.
Contradiction by assumption.
\end{proof}