test/phase5/exact-relational-replacement-local-failure.tex


1
2
3
4
5
6
7
8

\begin{proposition}\label{phase5_relational_local_failure}
    For every set $A$ we have $A = A$.
\end{proposition}
\begin{proof}
    Fix $A$.
    Let $B = \{ y \mid \exists x\in A. y = y \}$.
    Follows.
\end{proof}